从 python 的列表中添加 2 个整数

Question

im doing this exercise basically to add the first 2 integers in a list in python, but my script shows it runs the for loop twice before it iterates to the next integer in a list.

my code is below, i added a print statement so i can see how it iterates the FOR loop inside a WHILE loop.

def add2(nums):
    count = 0
    ans = 0
    
    while count <= 2:
        count += 1
        print(f'count: {count}')
        
        for x in nums:
            ans += x
            print(f'ans: {ans}')

HOwever if i run my code, i get this result. Why is it adding the value of ans twice before it goes to the next iteration? add2([2,3,5]) count: 1 ans: 2 ans: 5 ans: 10 count: 2 ans: 12 ans: 15 ans: 20 count: 3 ans: 22 ans: 25 ans: 30

Answer 1

You don't need to overcomplicate this. Just use slicing to return the first to elements of the list.

simpler code

listNums = [1,2,3,4]
print(float(listNums[0])+float(listNums[1]))

output

3.0

This is based on your explanation of the problem.

---

Now using your logic of solving this proble, I would consider removing the while loop altogether but keeping the for loop. Though keeping the plain for loop will not give us our desired output because it will find the sum of every number in the list. Instead we can cut the list of at two elements. The below code shows how to do that.

your logic code

def add2(nums):
    count = 0
    ans = 0
    for x in nums[:2]:
        ans += x
    print(f'ans: {ans}')
add2([1,2,3,4])

output

ans: 3

Answer 2

It could be as simple as this:

ans=0
for i in range(len(nums)):
   ans+=nums[i]
   if i > 2:
      break