如何在子文件夹/子路径中运行 Express 应用程序

Question

So, I have a very simple Express.js application. My entry point, server.js , is reproduced below.

const express = require('express');
const app = express();


app.get('/', (req, res) => {
    res.status(200).send({ "message": "Welcome to the application. Express JS is outputting this JSON. " });
});

app.get('/all', (req, res) => {
    res.status(200).send({ "message": "All the things. " });
});


app.listen(3000, () => {
    console.log("Server is listening on port 3000");
});

When I run this program with the command node server.js it works fine, and I can access the app at http://localhost:3000 . Similarly, when I deploy it to a LAN server, I can access its IP and reach the app like http://192.168.100.105:3000 .

Now, what if instead, I want the application to run at http://192.168.100.105/app1 ? One way to do it would be to app the Express app to run on port 80 and reconfigure all routes to use app1 as the new base URL, but I do not have the privilege to (or otherwise cannot) override the application running on the default port. So, is there any other way to achieve the same thing without running it on port 80 ?

Answer 1

There are two approaches:

• Have the software you want to access on port 80 actual listen on port 80 (you have ruled this out)
• Have some other software listen on port 80 and relay requests to your software

The typical approach with the latter is to use an HTTP server (such as nginx) configured to act as a reverse proxy. It can be configured to map a specific path rather than everything.

You could also use something like port forwarding with iptables (which effectively makes the software listen on port 80 as well as its real port).

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Any of these options will require sufficient privileges so, given the limitations you hint at, this is probably impossible for you.