为什么我不能分隔字符串中的字母？

Question

I want to take all the letters in a string and put it in a array separately. But I am receiving some error and I could not figure out.

10 20 E:\FALL SEM 20-21\CS\C codes\Untitled3.c [Warning] passing argument 2 of 'strcpy' makes pointer from integer without a cast

My code is

#include<stdio.h>
#include<string.h>


char array[10][100],string[100];
int top=0;

void push(char elem)
{
    strcpy(array[top],elem);
    top++;
}

int main()
{
    printf("Enter the string: \n");
    fgets(string,100,stdin);
    int length;
    length=strlen(string);
    int i=0;
    while((string[i])!='\0')
    {
        push(string[i]);
        i++;
    }
    printf("%d",length);
}

Answer 1

strcpy() is for copying strings (sequences of characters terminated by a null-character). To use that, you should make strings from the characters and pass them. Also you have to fix the type of the argument of push() .

#include<stdio.h>
#include<string.h>


char array[10][100],string[100];
int top=0;

void push(const char* elem) /* use const char* to receive strings that won't be modified */
{
    strcpy(array[top],elem);
    top++;
}

int main(void)
{
    printf("Enter the string: \n");
    fgets(string,100,stdin);
    int length;
    length=strlen(string);
    int i=0;
    while((string[i])!='\0')
    {
        char str[2] = {string[i], '\0'}; /* create a string */
        push(str); /* and push that */
        i++;
    }
    printf("%d",length);
}