匹配字符串之间的正则表达式

Question

Hey everyone I have a question. I am new with regex and I found it a little bit confusing about the match. Let say I want to take the element between a pattern of number.

['1.Ab2 C34 2.kj4 nsb', '1.Dog Cat4 2.Bird6 Trex5']

Is it possible to just take whatever the element is between the number 1. and 2. ?

output = [[Ab2 C34], [Dog Cat4]]

Answer 1

Use re.findall :

inp = ['1.Ab2 C34 2.kj4 nsb', '1.Dog Cat4 2.Bird6 Trex5']
matches = [re.findall(r'\b1\.\s*(.*?)\s*2\.', x)[0] for x in inp]
print(matches)  # ['Ab2 C34', 'Dog Cat4']

Answer 2

Try something like this using search .

import re
new = [[re.search('1.(.*)2.', s).group(1)] for s in ['1.Ab2 C34 2.kj4 nsb', '1.Dog Cat4 2.Bird6 Trex5']]