python 正则表达式匹配所有文字字符之间的字符串

Question

i am new to python regex i am trying to write a regular expression to match a string between character which are literals

my_string = "```,null,")]}'\n[[\"102fb5\",\"```"

What I want is 102fb5 .

The regex I have written:

"```n\[\[\\\"((?:.|\n)*?)\\"```"

Answer 1

First of all, I would recommend you use a Python raw string, it would make your RegEx more readable, in the sense that you won't need to escape every backslash:

QUERY = r'```n\[\[\"((?:.|\n)*?)\"```'

However, I'm not sure why you're bothering to match the entire list-like structure, when you could just search for the "literals" themselves by identifying their quotation marks:

# \"(.*?)\"
# Match escaped quotation mark: \"
# Match the literal text: .*?
# Match the other escaped quotation mark: \"

>>> re.findall(r'\"(.*?)\"', '''```,null,")]}'\n[[\"102fb5\",```"'\n[[\"102fb5\",\"```''')

['102fb5', '102fb5']