如何在没有因子的情况下打印数字的因子数请查看我的代码

Question

#include<iostream>

using namespace std;

int main(){

    int N,i;
    int count=0;
    cin>>N;

    for(i=1;i<=N;i++){
        if(N%i==0){
            cout<<i<<" ";
            count++;
        }
  
    }

}

INPUT 6

OUTPUT 1 2 3 6 4

I want to print the Number of Factors which is 4 in this case Before the Factors. I did it few days ago but i forget that now please help me..

Answer 1

The easiest way to achieve what you want by putting the factors in the array. like: int k =0; arr[k++] = i;

now, first print the count and then traverse and print the array.

Answer 2

There is no need to cout on line 12 and it will work fine:). That is printing the "i" which are the numbers you don't need.

cout<<i<<" ";

This line remove it.

Edit: I reread and found that you wanted to print the factors after it. You could save it in a vector or an array.

#include <vector> // At the top of your program

std::vector<int> factors; // At the declaration step

factors.push_back(i); // Where your cout << "i" initially was

// After the cout of your count
for ( auto &factor : factors ){
    std::cout << factor << " ";
}