当模式不可用时如何从列表中打印最小的数字？

Question

I Would like to find Mode in python array or list, but if all numbers appears at only once(or we can say there is no Mode) I wanted to print smallest number.

n_num = [64630, 11735, 14216, 99233, 14470, 4978, 73429, 38120, 51135, 67060]

from statistics import mode


def mode(n_num):
            n_num.sort()
            m = min(n_num)
            return m
print(str(mode(n_num)))

Answer 1

You can use multimode() from the statistics package instead of mode() . This will return multiple values when there is more than one mode to choose from. You can take the min() from that:

from statistics import multimode


n_num = [10, 9, 1, 2, 3, 4]
min(multimode(n_num))
# 1

n_num = [10, 9, 1, 2, 3, 4, 9, 10 ]
min(multimode(n_num))
#9

[Note: this requires python 3.8]

Answer 2

try to use the try statement

import statistics

def special_mode(iterable):
    try:
        result = statistics.mode(iterable)
    except statistics.StatisticsError: # if mode() fail, it do min()
        result = min(iterable)
    return result

mylist = [0, 1, 6, 9, 1, -7]
print(special_mode(mylist))
# return the 1 because of the mode function

mylist = [0, 1, 6, 9, -7]
print(special_mode(mylist))
# return the -7 beacuse it's the smallest

hope it was helpful

Answer 3

Python already has a min and max function built-in to find the smallest and largest values in a list

n = [64630, 11735, 14216, 99233, 14470, 4978, 73429, 38120, 51135, 67060]

smallest_number = min(n)
largest_number = max(n)