如何在 PowerShell 中找到包含他部分姓名的文件

Question

I'm new to PowerShell and on StackOverflow.

I'm trying to write a script which gives me the Total Path to a *.pdf file, My File Name is in a variable (I get it before with previous part of code) for example: $myVariable.Nom

After I try to find my file with this:

Get-ChildItem -Path "c:\myPath\" -Filter $myVariable.Nom 

But it doesn't work. I think I have a mistake where I try to filter with my File Name in the ChildItem command but don't know how to use it correctly.

The goal is (if myVariable.Nom = "TOTO" for example) to have c:\myPath\TOTO.pdf

Can anyone help me? Thanks.

Answer 1

The -Filter parameter on Get-ChildItem supports a wildcard search using * or ? . Your code is pretty close to what you're looking for, you just need to add * .

Get-ChildItem -Path "c:\myPath\" -Filter "*$($myVariable.Nom)*"

Note that I'm using * at the beginning and end of the variable,

In your example, you know that the File Name is TOTO so you could use * only at the end of the Filter :

-Filter "$($myVariable.Nom)*"

Remember that you can add the -Recurse flag on Get-ChildItem if you want to search recursively.

Now if you want to get the FullName (Total Path) you can use any of the examples below:

# Example 1
(Get-ChildItem -Path "c:\myPath\" -Filter "*$($myVariable.Nom)*").FullName

# Example 2
$var = Get-ChildItem -Path "c:\myPath\" -Filter "*$($myVariable.Nom)*"
$var.FullName

# Example 3
Get-ChildItem -Path "c:\myPath\" -Filter "*$($myVariable.Nom)*" |
Select-Object -Expand FullName

Edit

Following your second question, how to deal with a CSV with no headers:

$path = 'C:\path\to\csv.csv'

# Note: I'm using -Delimiter ';' because as you have shown,
# you are using semicolon as delimiter, however, if the delimiter
# are commas there is no need to use it.

$csv = Import-Csv $path -Delimiter ';' -Header 'Name','Qte'

# Now you can loop through it to find the files:

foreach($file in $csv)
{
    $var = Get-ChildItem -Path "c:\myPath\" -Filter "*$($file.Name)*"
    0..$file.Qte | foreach-object {
        $var.FullName
    }
}

Answer 2

Thank you for your answers: It's work fine !!

Now i want to improve it a litle bit: In my CSV i have 2 column: in the previous example i called the first column "Name" this is why i used myVariable.Name) for example:

Name;Qte
TOTO;1
TITI;3

Now how i can select the first column if i didn't have name on first line? file like this one for example:

TOTO;1
TITI;3

Thank you