简体   繁体   English

如何将 lambda function 转换为常规 function?

[英]How to convert a lambda function into a regular function?

a_min = [
    min(map(str.strip, x[0].split(',')),
        key=lambda i: int(str.strip(i).split('-')[-1])) for x in lst
]

I am trying to change the lambda into a regular function is there any way to do this?我正在尝试将 lambda 更改为常规 function 有什么办法吗?

It's simply a normal method with one argument, that return a value:它只是一个带有一个参数的普通方法,它返回一个值:

def min_key_method(i):
    return int(str.strip(i).split('-')[-1])

Usage:用法:

a_min = [
    min(map(str.strip, x[0].split(',')), key=min_key_method) for x in lst
]

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM