需要转换为lambda函数

Question

i try to write this function to lambda function,I tried a lot of options and I could not success:

 def getitem_rlist(s, i):
    while i > 0:    
      s, i = rest(s), i - 1
    return first(s)

I know to begin with:

getitem_rlist=lambda s,i:....?

thanks! in to example if: s=(1,(2,(3,4))) then getitem_rlist(a,2))# -> 3 the function need to return the element at index i of recursive list s

Answer 1

getitem_rlist=lambda s,i: getitem_rlist(s[1:][0],i-1) if i > 0 else s[0]

maybe what you want .... Its hard to tell withpout knowing what those other methods do ...

>>> getitem_rlist=lambda s,i: getitem_rlist(s[1:][0],i-1) if i > 0 else s[0]
>>> s=(1,(2,(3,4)))
>>> getitem_rlist(s,2)
3