如何在 PHP 的 class 构造函数中将数组作为参数传递

Question

I'm trying to pass these parameters in my class constructor:

1. $tableName : Database table name.
2. $id : ID field name of my database table.
3. $tableFields : Field names of my database table.

Parameter 1 and 2 always will be only 1, but parameter 3 is variable, maybe 2, maybe 4 or maybe 15.

So, I need to save it into an array, but I'm not sure how to do it.

Guys, can you help me to understand this?

<?php
    class GenerateCrud {
    
        // Properties.
        
            public $tableName;
            public $id;
            public $tableFields = array();
    
        // Constructor.
        
            function __construct($tableName, $id, $tableFields){
                $this->tableName = $tableName;
                $this->id = $id;
                $this->tableFields[] = $tableFields;
            }
    }
    
    $myObject = new GenerateCrud('users_test', 'id', 'field1', 'field2', 'field3', 'field4');
?>

Answer 1

Add:

$this->tableFields = $tableFields;

And:

$myObject = new GenerateCrud('users_test', 'id', ['field1', 'field2', 'field3', 'field4']);