您能否将一个具有固定单词列表的文件与一个在 python 中每 10 秒更新一次单词的文件进行比较？

Question

f1 = open("C:/Users/user/Documents/intro.txt", "r")  
f2 = open("C:/Users/user/Desktop/intro1.txt", "r")  
  
i = 0
  
for line1 in f1:
    i += 1
      
    for line2 in f2:
          
        
        if line1 == line2:  
            print("Line ", i, ": IDENTICAL")       
        else:
            print("Line ", i, ":")
            print("\tFile 1:", line1, end='')
            print("\tFile 2:", line2, end='')
        break
f1.close()                                       
f2.close() 

Can this method be used to compare them?
I tried alot of methods but i dont see any solutions If anyone could help me that would be great! I am fairly new to python

Answer 1

The above code would compare every line in the file to every line in the other file for each line. You would want to compare them by the same index.

with open("C:/Users/user/Documents/intro.txt", "r") as f1:
    lines1 = f1.readlines()

with open("C:/Users/user/Desktop/intro1.txt", "r") as f2:
    lines2 = f2.readlines()

length1 = len(lines1)
length2 = len(lines2)

if length1 == length2:
    for i in range(length1):
        line1 = lines1[i]
        line2 = lines2[i]

        if lines1[i] == lines2[i]:
            print("Line ", i, ": IDENTICAL")
        else:
            print("Line ", i, ":")
            print("\tFile 1:", line1, end='')
            print("\tFile 2:", line2, end='')
            break
else:
    print("Unequal length: ", length1, " ", length2)

Answer 2

In addition to my upper comment, here is the code to easy make hash for a file:

import hashlib

def hash_file(filename):
   """"This function returns the SHA-1 hash
   of the file passed into it"""

   # make a hash object
   h = hashlib.sha1()

   # open file for reading in binary mode
   with open(filename,'rb') as file:

       # loop till the end of the file
       chunk = 0
       while chunk != b'':
           # read only 1024 bytes at a time
           chunk = file.read(1024)
           h.update(chunk)

   # return the hex representation of digest
   return h.hexdigest()