[英]Iterate over elements in tuple (Python)
I am new in programming, and for practice reasons, I trying to iterate over elements in a tuple and after give to each different element an index.我是编程新手,出于实践原因,我尝试迭代元组中的元素,然后为每个不同的元素提供一个索引。
I have a problem iterating over tuples, here is my code:我在迭代元组时遇到问题,这是我的代码:
ps: I use enumerate
in order to keep an index for each tuple. ps:我使用
enumerate
来为每个元组保留一个索引。
myList = [(5, 7, 24), (0, 6, 10), (0, 3, 24), (1, 3, 100), (7, 10, 15)]
for tup in myList:
for x, y, z in enumerate (tup):
print(x, y, z)
But i get the this error:但我得到这个错误:
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
<ipython-input-72-cfb75f94c0bb> in <module>
17 myList = [(5, 7, 24), (0, 6, 10), (0, 3, 24), (1, 3, 100), (7, 10, 15)]
18 for tup in myList:
---> 19 for x, y, z in enumerate (tup):
20 print(x, y, z)
ValueError: not enough values to unpack (expected 3, got 2)
I gave 3 elements to unpack and I got anyway that error.我给了 3 个要解包的元素,但无论如何我都得到了那个错误。 Which is the correct way to unpack tuples of 3 elements?
哪个是解包 3 个元素的元组的正确方法?
I gave 3 elements to unpack and I got anyway that error.
我给了 3 个要解包的元素,但无论如何我都得到了那个错误。 Which is the correct way to unpack tuples of 3 elements?
哪个是解包 3 个元素的元组的正确方法?
The problem is that the for
loop is basically unpacking the tuple for you already.问题是
for
循环基本上已经为您解包了元组。 For example:例如:
myList = [(5, 7, 24), (0, 6, 10), (0, 3, 24), (1, 3, 100), (7, 10, 15)]
for tup in myList:
for x in tup:
print(x)
To use enumerate()
correctly, you need to unpack the two elements that are returned from it:要正确使用
enumerate()
,您需要解包从中返回的两个元素:
myList = [(5, 7, 24), (0, 6, 10), (0, 3, 24), (1, 3, 100), (7, 10, 15)]
for tup in myList:
for i, x in enumerate(tup):
print(i, x)
If instead, you want the index of each tuple in the parent list, you need to enumarate(myList)
in the outer loop:相反,如果您想要父列表中每个元组的索引,则需要在外循环中
enumarate(myList)
:
for i, (x, y, z) in enumerate(myList):
print(i, x, y, z)
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.