遍历Python字典中的部分元组键

Question

I am working on an optimization project where I have a series of dictionaries with tuples as keys and another dictionary (a decision variable with Gurobi) where the key is the first element of the tuples in the other dictionaries. I need to be able to do the following:

data1 = {(place, person): q}
data2 = {person: s}
x = {place: var}

qx = {k: x[k]*data1[k] for k in x}
total1 = {}
for key, value in qx.items():
    person = key[1]
    if person in total1:
        total1[person] = total1[person] + value
    else:
        total1[person] = value
total2 = {k: total1[k]/data2[k] for k in total1}

(Please note that the data1, data2, and x dictionaries are very large, 10,000+ distinct place/person pairs).

This same process works when I use the raw data in place of the decision variable, which uses the same (place, person) key. Unfortunately, my variable within the Gurobi model itself must be a dictionary and it cannot contain the person key value.

Is there any way to iterate over just the first value in the tuple key?

EDIT: Here are some sample values (sensitive data, so placeholder values):

data1 = {(1, a): 28, (1, c): 57, (2, b): 125}
data2 = {a: 7.8, b: 8.5, c: 8.4}
x = {1: 0.002, 2: 0.013}

Values in data1 are all integers, data2 are hours, and x are small decimals.

Outputs in total2 should look similar to the following (assuming there are many other rows for each person):

total2 = {a: 0.85, b: 1.2, c: 1.01}

This code is essentially calculating a "productivity score" for each person. The decision variable, x, is looking only at each individual place for business purposes, so it cannot include the person identifiers. Also, the Gurobi package is very limiting about how things can be formatted, so I have not found a way to even use the tuple key for x.

Answer 1

Generally, the most efficient way to aggregate values into bins is to use a for loop and store the values in a dictionary, as you did with total1 in your example. In the code below, I have fixed your qx line so it runs, but I don't know if this matches your intention. I also used total1.setdefault to streamline the code a little:

a, b, c = 'a', 'b', 'c'
data1 = {(1, a): 28, (1, c): 57, (2, b): 125}
data2 = {a: 7.8, b: 8.5, c: 8.4}
x = {1: 0.002, 2: 0.013}

qx = {place, person: x[place] * value for (place, person), value in data1.items()}
total1 = {}
for (place, person), value in qx.items():
    total1.setdefault(person, 0.0)
    total1[person] += value
total2 = {k: total1[k] / data2[k] for k in total1}

print(total2)
# {'a': 0.0071794871794871795, 'c': 0.013571428571428571, 'b': 0.19117647058823528}

But this doesn't produce the result you asked for. I can't tell at a glance how you get the result you showed, but this may help you move in the right direction.

It might also be easier to read if you moved the qx logic into the loop, like this:

total1 = {}
for (place, person), value in data1.items():
    total1.setdefault(person, 0.0)
    total1[person] += x[place] * value
total2 = {k: total1[k] / data2[k] for k in total1}

Or, if you want to do this often, it might be worth creating a cross-reference between persons and their matching places, as @martijn-pieters suggested (note, you still need a for loop to do the initial cross-referencing):

# create a list of valid places for each person
places_for_person = {}
for place, person in data1:
    places_for_person.setdefault(person, [])
    places_for_person[person].append(place)
# now do the calculation
total2 = {
    person: 
    sum(
        data1[place, person] * x[place]
        for place in places_for_person[person]
    ) / data2[person]
    for person in data2
}

Answer 2

For creating a new dictionary removing the tuple:

a, b, c = "a", "b", "c"
data1 = {(1, a): 28, (1, c): 57, (2, b): 125}
total = list()

spot = 0 
for a in data1:
    total.append(list(a[1])) # Add new Lists to list "total" containing the Key values
    total[spot].append(data1[a]) # Add Values to Keys judging from their spot in the list
    spot += 1 # to keep the spot in correct place in lists

total = dict(total) # convert it to dictionary
print(total)

Output:

{'a': 28, 'c': 57, 'b': 125}