在线检查两个条件

Question

I have the following lines and I want to match the first one based one the condition that it starts with a '%' and contains a '=' sign:

% This comment is = True

% This comment is equal true

I want to use python's re module to be able to extract the first sentence on the basis that it starts with a % and contains a = .

So far, I have gathered that I need something like:

...
if re.match('^%' ,line):
    ...

but cannot figure out the rest. Thank you!

Answer 1

You really don't need regex for this:

if line[0] == '%' and '=' in line:

OR

if line.startswith('%') and '=' in line:

That being said, you can use regex like this:

if re.match('%.*='):

Or better yet:

pattern = re.compile('%.*=')

...

if pattern.match(line):

re.match already implies that your regex begins with ^ .

If you don't want to allow %= , you still don't really need regex, but it's a bit simpler to use it. Without regex you can do something like

if line[0] == '%' and line[1] != '=' and '=' in line[2:]:

Using regex, you can do

if re.match('%[^=]+=', line):

I would argue that the second is more elegant.