[英]How to calculate array.reduce from two MongoDb collections
I have two Mongo Db collection.我有两个 Mongo Db 集合。 Relation is 1 to 1. I need to make array.reduce on base of both this collection.
关系是 1 到 1。我需要在这两个集合的基础上制作 array.reduce。 Something like:
就像是:
CollectionA: [
{ _id: 1, valueA: 234, idB: 1 },
{ _id: 2, valueA: 64, idB: 2 },
{ _id: 3, valueA: 456, idB: 3 },
]
CollectionB: [
{ _id: 1, valueB: 678 },
{ _id: 2, valueB: 11 },
{ _id: 3, valueB: 4005 },
]
I need to get sum of:我需要得到总和:
sum(valueA - valueB)
Is it possible to do with one request to Database?是否可以对数据库进行一次请求? If not what is the most elegant way?
如果不是最优雅的方式是什么?
You can use aggregation-pipeline to get the results you are looking for.您可以使用聚合管道来获得您正在寻找的结果。
Your query should look something like this:您的查询应如下所示:
db.CollectionA.aggregate([
{
$lookup: {
from: 'B',
localField: 'idB',
foreignField: '_id',
as: 'objB'
}
},
{ $unwind: '$objB' },
{
$project: {
subField: {
$subtract: ['$valueA', '$objB.valueB']
}
}
},
{
$group: {
_id: null,
sum: {
$sum: '$subField'
}
}
},
{
$project: {
_id: 0
}
}
]);
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