简体   繁体   English

如何从两个 MongoDb 集合计算 array.reduce

[英]How to calculate array.reduce from two MongoDb collections

I have two Mongo Db collection.我有两个 Mongo Db 集合。 Relation is 1 to 1. I need to make array.reduce on base of both this collection.关系是 1 到 1。我需要在这两个集合的基础上制作 array.reduce。 Something like:就像是:

CollectionA: [
  { _id: 1, valueA: 234, idB: 1 },
  { _id: 2, valueA: 64, idB: 2 },
  { _id: 3, valueA: 456, idB: 3 },
]

CollectionB: [
  { _id: 1, valueB: 678 },
  { _id: 2, valueB: 11 },
  { _id: 3, valueB: 4005 },
]

I need to get sum of:我需要得到总和:

sum(valueA - valueB)

Is it possible to do with one request to Database?是否可以对数据库进行一次请求? If not what is the most elegant way?如果不是最优雅的方式是什么?

You can use aggregation-pipeline to get the results you are looking for.您可以使用聚合管道来获得您正在寻找的结果。

Your query should look something like this:您的查询应如下所示:

db.CollectionA.aggregate([
    {
        $lookup: {
            from: 'B',
            localField: 'idB',
            foreignField: '_id',
            as: 'objB'
        }
    },
    { $unwind: '$objB' },
    {
        $project: {
            subField: {
                $subtract: ['$valueA', '$objB.valueB']
            }
        }
    },
    {
        $group: {
            _id: null,
            sum: {
                $sum: '$subField'
            }
        }
    },
    {
        $project: {
            _id: 0
        }
    }
]);

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM