Excel：如何在包含字符串的列中查找单元格并在另一列行中返回单元格的值？

Question

Python with Excel: If a cell in a column contains string, return cell value three cells over to the right.

Trying to come up with a Python script to:

1. look through an excel workbook
2. look through a specified column
3. if the column contains a string, ie 'daily sales'
4. return the cell value three columns over

ie: If Column E contains 'string' at E25, return the cell value in H25.

I tried the following in python with excel file living in the same directory as my python file:

import openpyxl

wb = openpyxl.load_workbook('example-workbook.xlsx')
sheet = wb.activelist(sheet.columns)[1]

for cellObj in list(sheet.columns)[4]:
    print(cellObj.value)

Column E corresponds with column 4.

I'm able to return all values in Column E using the above.

Answer 1

Here's a very literal implementation of the steps outlined in your question. It makes use of the worksheet iter_cols() method to iterate through the target column values looking for the target string and when if finds it—assuming it does—it uses the offset() cell method to access the desired cell value. Otherwise it raises an exception. The methods of the Cell class are in the openpyxl.cell.cell module and documented here . Kudos to @Charlie Clark for pointing it out to me.

import openpyxl
from openpyxl.utils.cell import column_index_from_string

class NotFoundError(LookupError):
    ''' Exception raised if target string isn't found. '''
    def __init__(self, target_string, column, excel_filepath):
        self.target_string = target_string
        message = (f'{target_string!r} target string not found in column '
                   f'{column!r} of Excel file {excel_filepath!r}')
        super().__init__(message)


def get_offset_column(excel_filepath, column, target_string, offset):
    ''' Search column of specified workbook for target string and return value of
        cell offset a given number of columns from that one.
    '''
    wb = openpyxl.load_workbook(excel_filepath)
    ws = wb.active
    column_index = column_index_from_string(column)

    # Look through the cells of the specified column.
    # If a cell contains target string, return value of the cell at offset column.
    cells = next(ws.iter_cols(min_col=column_index, max_col=column_index)) # Only one col.
    for cell in cells:
        if cell.value == target_string:
            return cell.offset(column=offset).value
    else:
        raise NotFoundError(target_string, column, excel_filepath)


if __name__ == '__main__':
    result = get_offset_column('example-workbook.xlsx', 'E', 'daily sales', 3)
    print(result)  # -> 42

The printed result shown was from running it on the following example-workbook.xlsx file I created for testing purposes: