Python 在不应该打印的时候打印，而打印不应该打印的内容

Question

---

animals = [('dog','Fort','brown'), ('dog', 'Nutmeg', 'brown'), ('cat', 'Oreo', 'black'), ('cat','Tiger','brown'), ('dog', 'Taco', 'white'), ('cat', 'Menoly', 'calico')]

for animal in animals: 
    print(animal[1] + ' is a ' + animal[2] + " " + animal[0])

color = input("Please choose one of the above colors: ").lower() 

for animal in animals:
    if color in animal[2]:
        print(animal[1] + ' is ' + color)
    else:
        print('No pets are ' + color)
        break

---

Output should be:
Fort is brown
Nutmeg is brown
Tiger is brown

Why is it printing out?:
Fort is brown
Nutmeg is brown
No pets are brown

Answer 1

In your code, if the condition is not True, it breaks.

if color == animal[2]:  #==== Use == instead of in
        print(animal[1] + ' is ' + color) 
    else:
        print('No pets are ' + color) #===== Printing this
        break #====== Break. Because the condition: color==animal[2] were not met and break broke out of the loop

You can use list comprehension and check if the list is empty or not.

color = input("Please choose one of the above colors: ").lower() 
x=[animal[1]+" is "+color for animal in animals if color==animal[2]]
if x==[]:
    print('No pets are ' + color)
else:
    for j in x:
        print(j)

Answer 2

Your loop prints "No pets are ..." too early.

Logically, it should wait to print that message after all pets have been processed and no matches were found. Instead, it prints that message when the current pet does not match.