打印两个表中的所有字段，并使用 ORACLE CASE 语句基于列将一些列值设置为空

Question

I need to print all columns but for some I need to print null using CASE in Oracle

| Db fields     | Male    |Female|Trans |
| ------------- | ------- |------|------|
|customer_id    | Y       |      |      |
|customer_name  | Y       |   Y  |  Y   |
|address        |         |   Y  |      |
|city           | Y       |   Y  |  Y   |
|state          | Y       |   Y  |  Y   |
|zip_code       |         |   Y  |      |
|customer_type  | Y       |      |  Y   |

PS-This is not a table

I was trying to write this query -

select
case
     when c.customer_type='Female' then customer_id is null 
     when c.customer_type='Trans' then customer_id is null
case(address)
     when c.customer_type='Male' then address is null 
     when c.customer_type='Trans' then address is null
case(zip_code)
     when c.customer_type='Male' then zip_code is null 
     when c.customer_type='Trans' then zip_code is null
case(customer_type)
    when c.customer_type='Female' then customer_type is null
end
c.customer_id, c.customer_name, c.address, c.city, c.state,c.zip_code,c.customer_type, e.employee_number, e.employee_name from customers c, employees e where e.customer_id=c.customer_id where c.customerid=1;

This is not working .

============================================================

The tables and columns just for reference:

CREATE TABLE customers(
  customer_id number(10) NOT NULL,
  customer_name varchar2(50) NOT NULL,
  address varchar2(50),
  city varchar2(50),
  state varchar2(25),
  zip_code varchar2(10),
  customer_type varchar2(10),
  CONSTRAINT customers_pk PRIMARY KEY (customer_id)
);
insert into customers values(1,'A','Japan','Tokyo','J',001,'Male');
insert into customers values(2,'B','UK','London','U',002,'Female');
insert into customers values(3,'C','China','Tibet','S',003,'Trans');
insert into customers values(4,'D','South korea','Souel','S',004,'Female');

CREATE TABLE employees(
  employee_number number(10) NOT NULL,
  employee_name varchar2(50) NOT NULL,
  customer_id number(10),
  CONSTRAINT employees_pk PRIMARY KEY (employee_number),
  CONSTRAINT fk_customers FOREIGN KEY (customer_id) REFERENCES customers(customer_id));


insert into employees values(101,'titu',1);
insert into employees values(102,'kitu',2);
insert into employees values(103,'pitu',3);
insert into employees values(104,'yitu',4);

Answer 1

You could print the output as a single column that consists of multiple concatenated columns. From your (deleted) previous question you indicated that this is for a label, so you don't need multiple columns. In the code below, different columns are concatenated based on the value of customer_type.

This could work:

SELECT 
  CASE 
    WHEN customer_type = 'Male' THEN
      c.customer_id ||' -> '|| c.customer_name ||' -> '|| c.city ||' -> '|| c.state ||' -> '|| c.customer_type  
    WHEN customer_type = 'Female' THEN
      c.customer_name ||' -> '|| c.address ||' -> '|| c.city ||' -> '|| c.state ||' -> '|| c.zip_code  
    WHEN customer_type = 'Trans' THEN
      c.customer_name ||' -> '|| c.city ||' -> '|| c.state ||' -> '|| c.customer_type     
  END as "Output"
  FROM customers c 
       JOIN employees e ON e.customer_id=c.customer_id;


Output                                                                                                                                                                                                   
---------------------------
1 -> A -> Tokyo -> J -> Male
B -> UK -> London -> U -> 2
C -> Tibet -> S -> Trans
D -> South korea -> Souel -> S -> 4