将多行压缩为由其他列熊猫聚合的 1

Question

How do I select a column that is grouped by other columns and put all the values of the column in 1 row (in a list). Input:

PropID    Manager    Manager_email      date
  1         A         a@aol.com       2021-02-01
  1         A         a@aol.com       2021-02-02
  1         A         a@aol.com       2021-02-03
  1         A         a@aol.com       2021-02-04
  2         B         b@aol.com       2021-02-08
  2         B         b@aol.com       2021-02-10
  2         B         b@aol.com       2021-02-12
  2         B         b@aol.com       2021-02-16

Desired Output:

PropID    Manager    Manager_email                      date
  1         A         a@aol.com       [2021-02-01,2021-02-02,2021-02-03,2021-02-04]
  2         B         b@aol.com       [2021-02-08,2021-02-10,2021-02-12,2021-02-16]

Answer 1

试试这个：

df.groupby(['PropID','Manager','Manager_email'])['date'].agg(list)