如何扫描目录中的文件夹并获取末尾编号最高的文件夹-python

Question

i am really new to python and i am trying to automate procedure. i have some folders and i want to enter the folder with the highest number at the end. in the picture i have some folders. and i want to take the folder with the highest number at the end. for example in this picture, folder_4 this is what i tried so far. i do not know how to continue or if my code is any effective.

import os
import shutil
import glob

path="N:\QA\Automation\Projects\AT_Projects"
projectlist = os.listdir(path)
for project in projectlist:
    projectdir = path + "\\" + project
    file_path=[]
    print(projectlist)
 
    if os.path.isdir(projectdir):
        folders=os.listdir(projectdir)
        for folder in folders:
            file_path=folder
        
      
            if os.folderdir.isdir(folder):
            
               print('true')

   
    else:
        print("done")

I want to scan the folder and at the end enter folder_4 to get something from it.

how do I do this scan?

Answer 1

Assuming everything is in the same folder, you can do something like this:

from pathlib import Path

p = Path.cwd()  # Alternatively, use Path(<your folder path>) to point to another folder
sorted_folders = list(sorted(p.glob("*[0-9]/"), key=lambda x: int(x.name.split("_")[-1])))

This works from the folder containing the folders you want to sort by.

Breaking this down:

1. Using pathlib.Path you get a Path object for the current working directory
2. Use Path.glob with the pattern "*[0-9]/", which gives you a generator for everything in the directory (all your folders) that end with a number
3. Use sorted, with a key that is "split the name on _ an take the last piece of that name", eg "folder_1" -> ["folder", "1"]. We apply int so that the last element here is treated as a number, not a string
4. create a list so that you have the folders in order

If you then want the folder with the largest number, you can take the last member of your list

sorted_folders[-1]