子函数出错时如何终止Python中的一行代码

Question

So I have some code that is in its simple structure like the code below. Basically I have two functions. One function takes the other as an input. What I want to have happen is if the function1 fails and would error, that it "exits" out and skips over the function2(function1()) line and continues on without ending the entire process.

def function1():
     try:
          something = some_function()
          return something
     except:
          exit()

def function2(input):
     operate(input)


function2(function1())

Anyone have any ideas/suggestions?

Answer 1

instead of exit , have it return an expected output --

def function1():
     try:
          something = some_function()
          return something
     except Exception as e:
          print(f"Something went wrong: {e}")
          return False

Then you can act based on it's boolean condition --

def function2(input):
    if input:
        operate(input)

Answer 2

Ending the entire process is exactly what exit does. You should just let the exception go uncaught, and execute function2(function1()) in a try statement.

def function1():
    return some_function()

def function2(i):
    operate(i)

try:
    function2(function1())
except Exception:
    pass

If function1 isn't a function you have control over, you can specifically catch SystemExit that exit raises, though I would do so in as small a block of code as possible.

try:
    x = function(1)
except SystemExit:
    pass
else:
    function2(x)