[英]one-liner for convert hex string to char array
This is probably a duplicate of hex string to unsigned char but with different input这可能是十六进制字符串到无符号字符的重复,但输入不同
I want to read hex strings from txt file and tried to save it in array我想从 txt 文件中读取十六进制字符串并尝试将其保存在数组中
FF FF FF FF FF FF FF FF
0 3F 0 0 3 E0 0 1
7F 0 43 1 92 FF 0 AA
Expected output:预期输出:
unsigned char array[3][8] = {
0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,
0x0, 0x3F, 0x0, 0x0, 0x3, 0xE0, 0x0, 0x1,
0x7F, 0x0, 0x43, 0x1, 0x92, 0xFF, 0x0, 0xAA
};
Note: Line ending is important.注意:行尾很重要。 Some lines representing less than 8 bytes
一些行表示少于 8 个字节
I could show you 50 lines of code but that is completely garbage.我可以给你看 50 行代码,但这完全是垃圾。 My question isn't there any one-liner std::something to achieve this?
我的问题是没有任何单行 std::something 来实现这一目标吗?
You can stream it:您可以流式传输它:
std::ifstream file(…);
std::vector<char> buf;
while(file)
{
int c;
file >> std::hex >> c;
buf.push_back(c);
}
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