[英]How to change values of every id in this nested object array?
I have data structure similar like this我有类似这样的数据结构
{"id": 1, "a": [{"id": 2, "b": [{"id": 3, "c": [{"id": 4}]}]}]}
I would like to change every id
to null
.我想将每个
id
更改为null
。
I know I could do loops and manually assign null
to id
.我知道我可以做循环并手动将
null
分配给id
。 Is there any easy way to do this in JavaScript?有没有什么简单的方法可以在 JavaScript 中做到这一点?
Bravo's comment was illuminating so I hope they don't mind if I expand on it here. Bravo 的评论很有启发性,所以我希望他们不介意我在这里展开讨论。
Turn the object into a string.将对象变成字符串。
Parse it back into an object again.再次将其解析回一个对象。
What I didn't know is that JSON.parse
has a "reviver" function that allows you to transform the string value as it's being parsed.我不知道的是
JSON.parse
有一个“reviver”函数,它允许您在解析字符串值时对其进行转换。
const data = {"id": 1, "a": [{"id": 2, "b": [{"id": 3, "c": [{"id": 4}]}]}]}; // Turn the data into a string const str = JSON.stringify(data); // Parse the string back to an object // but using the reviver function to turn the value of any id // keys to null const newObj = JSON.parse(str, (key, value) => key === 'id' ? null : value); console.log(newObj);
Without changing the object to a JSON string, you could use recursion:在不将对象更改为 JSON 字符串的情况下,您可以使用递归:
function clearIds(obj) { if ("id" in Object(obj)) obj.id = null; Object.values(Object(obj)).forEach(clearIds); } // Demo let obj = {"id": 1, "a": [{"id": 2, "b": [{"id": 3, "c": [{"id": 4}]}]}]}; clearIds(obj); console.log(obj);
This mutates the given object in place.这会在适当的位置改变给定的对象。
For fun: the same function as a one-liner:为了好玩:与单行相同的功能:
const clearIds = o => "id" in Object(o) && (o.id = null) || Object.values(Object(o)).forEach(clearIds); // Demo let obj = {"id": 1, "a": [{"id": 2, "b": [{"id": 3, "c": [{"id": 4}]}]}]}; clearIds(obj); console.log(obj);
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