Scala：创建带有变量的 case class 的多个序列

Question

I'm trying to generate dynamically a sequence of case class but I'm blocked at one point. I want to use variables in this function.

Here's an example of what I did (which is working as expected):

case class Example(first_name: String, last_name: String)

Object Example{
 def createRecords(number: Int) : Seq[Example]{
     Seq.fill(number)(Example("Bob", "Marley"))
}}

The thing I want to do now is to have the first_name and the last_name as variables in the generating process that would look like something like this:

Object Example{
 def createRecords(number: Int) : Seq[Example]{
     Seq.fill(number)(
        val first_name = generateRandomFirstName()
        val last_name = generateRandomLastName() 
        Example(first_name, last_name))
}}

Is there an easy way to be able to do that or I need to simply refactor my code and generate what I need with a standard loop?

Thanks in advance

Answer 1

Your code is actually very close, you just need to replace () with {} to turn the argument into an expression:

Seq.fill(number){
  val first_name = generateRandomFirstName()
  val last_name = generateRandomLastName()

  Example(first_name, last_name)
}

You can also just call the functions in the constructor:

Seq.fill(number)(
  Example(generateRandomFirstName(), generateRandomLastName())
)

Note that Seq is a generic interface so you should probably use an explicit type such as List or Vector to make sure you are getting the type you want.