如何使用 bash 将多个版本号不同的文件从一个目录复制到另一个目录？

Question

I have a folder /home/user/Document/filepath where I have three files namely file1-1.1.0.txt, file2-1.1.1.txt, file3-1.1.2.txt

and another folder named /home/user/Document/backuppath where I have to move files from /home/user/Document/folderpath which has file1-1.0.0.txt, file2-1.0.1.txt and file3-1.0.2.txt

1. task is to copy the specific files from folder path to backup path.

To summarize:

the below is the files.txt where I listed the files which has to be copied:

file1-*.txt
file2-*.txt

The below is the move.sh script that execute the movements
for file in `cat files.txt`; do cp "/home/user/Document/folderpath/$file" "/home/user/Documents/backuppath/" ; done

for the above script I am getting the error like

cp: cannot stat '/home/user/Document/folderpath/file1-*.txt': No such file or directory found
cp: cannot stat '/home/user/Document/folderpath/file2-*.txt': No such file or directory found

what I would like to accomplish is that I would like to use the script to copy specific files using * in the place of version numbers., since the version number may vary in the future.

Answer 1

You have wildcard characters in your files.txt. In your cp command, you are using quotes. These quotes prevent the wildcards to be expanded, as you can clearly see from the error message.

One obvious possibility is to not use quotes:

 cp /home/user/Document/folderpath/$file /home/user/Documents/backuppath/

Or not use a loop at all:

 cp $(<files.txt) /home/user/Documents/backuppath/

However, this would of course break if one line in your files.txt is a filename pattern which contains white spaces. Therefore, I would recommend a second loop over the expanded pattern:

while read file # Puts the next line into 'file'
do
  for f in $file # This expands the pattern in 'file'
  do
     cp "/home/user/Document/folderpath/$f" /home/user/Documents/backuppath
  done
done < files.txt