Function 名称被该函数的参数名称遮蔽

Question

Warning: The 5th edition of ECMAScript (ES5) forbids use of arguments.callee() in strict mode. Avoid using arguments.callee() by either giving function expressions a name or use a function declaration where a function must call itself. [ MDN ]

How does one reference the o function within itself in the following situation?

function o(o) { o(); }
o('not a function'); // TypeError: o is not a function

EDIT:

Why not rename the parameter/function?

1. I am debugging thousands of files of obfuscated JavaScript code.
2. My own personal opinion is that this problem should be avoidable via reflection alone, not refactoring.

EDIT:

In the above situation, I am looking for either a way to reference the function within itself or, alternatively, an explanation or a reference to a credible source as to why the parameter name shadows the function name .

Answer 1

Naming a parameter a name that another declared variable has makes it the value in the function. It ignores the other declaration(s) and uses the one in the parameters. The best thing to do is rename it, but if it is in the global scope, you can access it with window (HTML documents only). Just type window.functionName() and it will reference correctly. This only works if it was defined in the global scope with the var keyword!

 //global scope var a = 1 function b(a) { console.log(a) console.log(window.a) } b(2) //2 and then 1 function o(o) { console.log(++a) if(a < 5) window.o() //calls o() from global scope } o()

Answer 2

Parameter o of o function is not a string. It should be a reference to any function or function name.

function a() { console.log('a function'); }
function o(o) { console.log('o function'); o(); }
o(a); 
// o function
// a function

Answer 3

Used shift-refactor to implement the obvious ( rename ) solution, as I did not find another one:

$source('FunctionDeclaration,FunctionExpression').forEach(fd => {
  if(fd.name)
  {
    for (let param of fd.params.items) {
      if (param.name === fd.name.name) {
        $source(param).rename('randomParameterName');
        break;
      }
    }
  }
});