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为什么〜True在熊猫数据框条件下不起作用

[英]why does ~True not work in pandas dataframe conditional

I am trying to use switches to turn on and off conditionals in a pandas dataframe.我正在尝试使用开关来打开和关闭熊猫数据框中的条件。 The switches are just boolean variables that will be True or False.开关只是布尔变量,可以是 True 或 False。 The problem is that ~True does not evaluate the same as False as I expected it to.问题是 ~True 不会像我预期的那样评估与 False 相同的值。 Why does this not work?为什么这不起作用?

>>> dataframe = pd.DataFrame({'col1': [3, 4, 5, 6], 'col2': [6, 5, 4, 3]})
>>> dataframe
   col1  col2
0     3     6
1     4     5
2     5     4
3     6     3
>>> dataframe.loc[dataframe.col1 <= dataframe.col2]
   col1  col2
0     3     6
1     4     5
>>> dataframe.loc[(True) | (dataframe.col1 <= dataframe.col2)]
   col1  col2
0     3     6
1     4     5
2     5     4
3     6     3
>>> dataframe.loc[(False) | (dataframe.col1 <= dataframe.col2)]
   col1  col2
0     3     6
1     4     5
>>> dataframe.loc[(~True) | (dataframe.col1 <= dataframe.col2)]
   col1  col2
0     3     6
1     4     5
2     5     4
3     6     3
>>> dataframe.loc[(~(True)) | (dataframe.col1 <= dataframe.col2)]
   col1  col2
0     3     6
1     4     5
2     5     4
3     6     3
>>>

>>> dataframe  = pd.DataFrame({'col1': [1, 2, 3, 4], 'col2': [True, False, False, True]})
>>> dataframe
   col1   col2
0     1   True
1     2  False
2     3  False
3     4   True
>>> dataframe.loc[dataframe.col2]
   col1  col2
0     1  True
3     4  True
>>> dataframe.loc[not dataframe.col2]
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python3/dist-packages/pandas/core/generic.py", line 1537, in __nonzero__
    raise ValueError(
ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().
>>> dataframe.loc[dataframe.col2 == False]
   col1   col2
1     2  False
2     3  False

This is a pandas operator behavior (implemented from Numpy).这是一个 pandas 运算符行为(从 Numpy 实现)。

True is not a pandas object. True不是熊猫对象。 Instead it's a boolean.相反,它是一个布尔值。 So obviously, the ~ operator isn't meant to reverse booleans, only in Pandas.很明显, ~运算符并不意味着反转布尔值,仅在 Pandas 中。

As you can see:如你看到的:

>>> ~True
-2
>>> 

It gives -2 , which is the regular __invert__ magic method behavior.它给出-2 ,这是常规的__invert__魔术方法行为。

Therefore:所以:

>>> bool(-2)
True
>>> 

Gives True .给出True

Don't mix up Pandas and Python behavior, Pandas implements it's on __invert__ usage, example:不要混淆 Pandas 和 Python 的行为,Pandas 在__invert__用法上实现它,例如:

>>> ~pd.Series([True])
0    False
dtype: bool
>>> 

As you can see, in pandas (also Numpy), it inverts the booleans.如您所见,在 pandas(也是 Numpy)中,它反转了布尔值。 Therefor if you write:因此,如果你写:

>>> dataframe.loc[~pd.Series([True]).any() | (dataframe.col1 <= dataframe.col2)]
   col1  col2
0     3     6
1     4     5
>>> 

You can clearly see that it behaves equivalently as False .您可以清楚地看到它的行为等同于False

The best way here is with not :这里最好的方法是not

>>> dataframe.loc[(not True) | (dataframe.col1 <= dataframe.col2)]
   col1  col2
0     3     6
1     4     5
>>> 

I think '~' is not what you want, maybe you want to use 'not':我认为'~'不是你想要的,也许你想使用'not':

>>> dataframe.loc[(not True) | (dataframe.col1 <= dataframe.col2)]
   col1  col2
0     3     6
1     4     5

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