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如何在手机部分弹出window如图

[英]How to get pop up window in part of phone like the image

原文 2021-10-05 04:44:27 4 1 android/ kotlin

I am trying to make my own alarm app and want to have a partial view open up when an alarm activates no matter where in the phone I am at, like the image I am including.我正在尝试制作自己的闹钟应用程序，并希望在闹钟激活时打开部分视图，无论我在手机的哪个位置，就像我包含的图像一样。 Can I please get some tips on how I would do this, do I start an activity through an intent with the alarm manager?我能否获得一些关于如何执行此操作的提示，我是否通过警报管理器的意图开始一项活动？ Or can I just start a fragment?或者我可以开始一个片段吗？ Also, how do I get it to just be the little window, I prefer that, and do not want to launch a full screen view.另外，我如何让它成为小 window，我更喜欢它，并且不想启动全屏视图。 Apologies that I do not know much, I don't have anyone else to ask for advice.抱歉，我知道的不多，我没有其他人可以征求意见。 I am using kotlin, Thank you.我用的是kotlin，谢谢。

1 个解决方案

That's just a notification that has a button.那只是一个带有按钮的通知。

You'll find everything here: https://developer.android.com/training/notify-user/build-notification你会在这里找到一切： https://developer.android.com/training/notify-user/build-notification

To add a Button: https://developer.android.com/training/notify-user/build-notification#Actions添加按钮： https://developer.android.com/training/notify-user/build-notification#Actions

Just a hint: If you change the behaviour of your channel, clear your appdata or choose another id (Or even better: delete your channel via notificationManager if it's not needed anymore).提示：如果您更改频道的行为，请清除您的应用数据或选择另一个 ID（或者更好：如果不再需要，通过 notificationManager 删除您的频道）。 Otherwise the changes will not be applied.否则将不会应用更改。