简体   繁体   English

使用递归无循环查找字符串列表的所有子集

[英]Finding all subsets of a list of strings with recursion no loop

Is it possible to find all the subsets of a string list using only recursion and no loops?是否可以仅使用递归而不使用循环来查找字符串列表的所有子集? Would this require multiple methods?这需要多种方法吗?

UPDATE更新

The below Solution is not suitable as it finds only a subset of the sublists, still leaving it here as it may help the author.下面的解决方案不合适,因为它只找到了子列表的一个子集,仍然把它留在这里,因为它可能对作者有帮助。

This would be a solution:这将是一个解决方案:

public void findSubsets(List<String> list, int listSize)
{
    if(listSize <= 1)
    {
        System.out.println(list.subList(0, 1));
        return;
    }

    System.out.println(list.subList(0, listSize));
    findSubsets(list, listSize - 1);

}

Or if you need to return the Sub Lists:或者,如果您需要返回子列表:

public List<List<String>> findSubsets(List<String> list, int listSize, List<List<String>> subLists)
{

    if(listSize <= 1)
    {
        subLists.add(list.subList(0, 1));
        return subLists;
    }

    subLists.add(list.subList(0, listSize));
    return findSubsets(list, listSize - 1, subLists);

}

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM