接受任何通道的 go 函数

Question

I would like to write a function in go that takes a generic channel as an input. I'd like it to be able to accept any channel regardless of what type that channel is for. I assumed I could us func myFunc(channel chan interface{}) but I'm getting a compilation error when I try to pass my channel to it. Is there a way to do this in go?

Answer 1

chan interface{} and chan int are two distinct type definitions.

Consider this example:

package main

import (
    "fmt"
)

func myFunc(ch chan interface{}) {
    fmt.Println("I'm called")
}

func main() {
    ch := make(chan int)
    myFunc(ch)
    fmt.Println("Done")
}

This function panics with

cannot use ch (type chan int) as type chan interface {} in argument to myFunc

Let's change the type to chan interface{}

package main

import (
    "fmt"
)

func myFunc(ch chan interface{}) {
    fmt.Println("I'm called")
}

func main() {
    ch := make(chan interface{})
    myFunc(ch)
    fmt.Println("Done")
}

This compiles.

chan int is used as an example - anything else apart from chan interface{} as the type for ch will result in a panic.

If you absolutely want a function that you want to be able to call with any of chan int , chan string , chan customtype your only bet right now is to accept a plain interface{} .

As @mkopriva mentioned though, generics are coming soon.