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如何在 Go 中定义一个接受任意数量参数的函数类型?

[英]How to define a function type which accepts any number of arguments in Go?

I try to write a function which takes any other function and wraps a new function around it.我尝试编写一个函数,它接受任何其他函数并围绕它包装一个新函数。 This is what I have tried so far:这是我迄今为止尝试过的:

package main

import (
    "fmt"
)

func protect (unprotected func (...interface{})) (func (...interface{})) {
    return func (args ...interface{}) {
        fmt.Println ("protected");
        unprotected (args...);
    };
}

func main () {
    a := func () {
        fmt.Println ("unprotected");
    };
    b := protect (a);
    b ();
}

When I compile this I get the error:当我编译这个时,我收到错误:

cannot use a (type func()) as type func(...interface { }) in function argument

Why is a function without arguments not compatible to a function with a variable number of arguments?为什么没有参数的函数与具有可变数量参数的函数不兼容? What can I do to make them compatible?我该怎么做才能使它们兼容?

Update: The protected function should be compatible with the original:更新:受保护的功能应与原始功能兼容:

func take_func_int_int (f func (x int) (y int)) (int) {
    return f (1)
}

func main () {

    a := func (x int) (y int) {
        return 2 * x
    }
    b := protect (a)

    take_func_int_int (a)
    take_func_int_int (b)
}

Types are pretty concrete in Go. Go 中的类型非常具体。 You could try你可以试试

a := func(_ ...interface{}) {
    fmt.Println("unprotected")
}

func (...interface{}) does not mean "any function that takes any number of any kind of arguments", it means "only a function which takes a variable number of interface{} arguments" func (...interface{})并不意味着“任何函数接受任意数量的任何类型的参数”,它的意思是“只有一个函数接受可变数量的 interface{} 参数”

Alternatively rather than func(...interface{}) you can just use interface{} and the reflect package.或者,您可以只使用interface{}reflect包,而不是func(...interface{}) See http://github.com/hoisie/web.go for an example.有关示例,请参见http://github.com/hoisie/web.go

EDIT: Specifically, this:编辑:具体来说,这个:

package main

import (
    "fmt"
    "reflect"
)

func protect(oldfunc interface{}) (func (...interface{})) {
    if reflect.TypeOf(oldfunc).Kind() != reflect.Func {
        panic("protected item is not a function")
    }
    return func (args ...interface{}) {
        fmt.Println("Protected")
        vargs := make([]reflect.Value, len(args))
        for n, v := range args {
            vargs[n] = reflect.ValueOf(v)
        }
        reflect.ValueOf(oldfunc).Call(vargs)
    }
}

func main() {
    a := func() {
        fmt.Println("unprotected")
    }
    b := func(s string) {
        fmt.Println(s)
    }
    c := protect(a)
    d := protect(b)
    c()
    d("hello")
}

Ouput is输出是

Protected
unprotected
Protected
hello

EDIT: To answer the update编辑:回答更新

Like I said above, types are pretty concrete in Go.就像我上面说的那样,Go 中的类型非常具体。 The protect function returns a type func(...interface{}) which will never be assignable to func(int)int .保护函数返回一个类型func(...interface{}) ,它永远不能分配给func(int)int I think you're probably either over-engineering your problem or misunderstanding it.我认为你可能要么过度设计了你的问题,要么误解了它。 However, here's a highly discouraged code snippet that would make it work.然而,这是一个非常不鼓励的代码片段,可以让它工作。

First change protect to also return values:首先将保护更改为也返回值:

func protect(oldfunc interface{}) (func (...interface{}) []interface{}) {
    if reflect.TypeOf(oldfunc).Kind() != reflect.Func {
        panic("protected item is not a function")
    }
    return func (args ...interface{}) []interface{} {
        fmt.Println("Protected")
        vargs := make([]reflect.Value, len(args))
        for n, v := range args {
            vargs[n] = reflect.ValueOf(v)
        }
        ret_vals := reflect.ValueOf(oldfunc).Call(vargs)
        to_return := make([]interface{}, len(ret_vals))
        for n, v := range ret_vals {
                to_return[n] = v.Interface()
        }
        return to_return
    }
}

Then make a convert function:然后做一个转换函数:

func convert(f func(...interface{}) (func(int) int) {
    return func(x int) int {
        r := f(x)
        return r[0].(int)
    }
}

Then your call would look like然后你的电话看起来像

take_func_int_int(convert(b))

But I promise this isn't what you actually want to do.但我保证这不是你真正想要做的。

Step back and try to rework the problem.退后一步,尝试重新解决问题。 I've completely killed type-safety in these examples.在这些示例中,我已经完全消除了类型安全性。 What are you trying to accomplish?你想达到什么目的?

package main

import "fmt"

// Here's a function that will take an arbitrary number
// of `int`s as arguments.
func sum(nums ...int) {
    fmt.Print(nums, " ")
    total := 0
    for _, num := range nums {
        total += num
    }
    fmt.Println(total)
}

func main() {

    // Variadic functions can be called in the usual way
    // with individual arguments.
    sum(1, 2)
    sum(1, 2, 3)

    // If you already have multiple args in a slice,
    // apply them to a variadic function using
    // `func(slice...)` like this.
    nums := []int{1, 2, 3, 4}
    sum(nums...)
}

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