如何将带空格的字符串转换为在python中列出

Question

I want to convert a string to a list.

fName = input("Enter your First Name: \n")
lName = input("Enter your Last Name: \n")
location = input("Enter your Location: \n")

string = fName + " " + lName + " " + location

print(string)
print("String coverted to list :",string.split())
# Output : String coverted to list : ['name', 'name', 'location']

print("String coverted to list :\n",list(string))
# Output: String coverted to list : ['n', 'a', 'm', 'e', ' ', 'n', 'a', 'm', 'e', 'l', 'o', 'c', 'a', 't', 'i', 'o', 'n' ]

Desired Result :

#Output : [ namenamelocation]

Basically I do not want the list to get separated after spaces and want the term string to be a single index in list.

Answer 1

# remove spaces and then put into list
[string.replace(" ", "")]

To add, if you don't add the spaces at the beginning, you don't need to use .replace() , just the brackets []

string = [fName + lName + location]