如何使用 Revit API 激活（显示）视图（平面图或标高）？

Question

I am trying to activate a view using Revit API. What I want to do exactly is to display the level or floor plan view. So the view I want to activate ( I mean, I want this view to be actually shown on screen) already exists, and I can access its Id.

I have seen threads about creating, browsing, filtering views, but nothing on activating it... It's a Floor Plan view. (What I want is that by selecting a level/ floor plan, it displays that level/ floor plan on-screen(it's like opening that floor plan from the already existing Revit model to display on the user screen).

Answer 1

Here is an example how to switch to the default 3d-view https://thebuildingcoder.typepad.com/blog/2011/09/activate-a-3d-view.html

you can do the same with all other available views like this

    UIApplication uiapp = commandData.Application;
    UIDocument uidoc = uiapp.ActiveUIDocument;
  
    uidoc.ActiveView = yourview;

Answer 2

Super easy to do:

# normally you have the ui set at the start of your script
ui = __revit__.ActiveUIDocument 

# then just set the ActiveView as your view (not the ViewId)
ui.ActiveView = yourView

Answer 3

FilteredElementCollector viewCollector = new FilteredElementCollector(doc);

                viewCollector.OfClass(typeof(View));

                foreach (Element viewElement in viewCollector)
                {
                        yourview = (View)viewElement;
                      
                        break;  
                }
            }

            uidoc.ActiveView = yourview;