结构不显示在 C 中输入的值

Question

I'm trying to print the entered values from struct. Program is able to get all input values but after show() method call it does jumps out of the program in exit without displaying my entered values.

I'm not getting any error or warning at all.

Code:

#include<stdio.h>
#include<string.h>

struct Book{
    char *title;
    short price;
};

void show(struct Book b[],const short n){
    short i;
    printf("\nBOOK DETAILS");
    for(i=0;i<n;i++){
        printf("\nRecord no %d / %d",i+1,n); //exits after displaying this line
        printf("\nTitle : %s \nPrice: %d",b[i].title, b[i].price);
    }
}

void get(struct Book b[],const short n){
    short i;
    for(i=0;i<n;i++){
        printf("\nRecord no %d / %d",i+1,n);
        printf("\nEnter book title & price: ");
        scanf("%s %d",&b[i].title, &b[i].price);
    } 
    show(b,n);
}

int main()
{
    struct Book b[3];
    get(b,3);
    return 0;
}

Call sequence is like main() --> get() -->show(). I'm using Dev cpp compiler with .c extension of my code file.

Answer 1

title member of struct Book is just a pointer to char * , so when you define a struct Book structure, no memory has been allocated for its title .
Either define title as an array or allocate memory for it.