如何将由整数和浮点数组成的列表中的字符串列表转换为整数和浮点数？

Question

例如，我有列表 ['-1','9','7.8'] 如何将列表转换为 [-1,9,7.8] 而不必在全部转换为浮点数或全部转换为浮点数之间进行选择整数？

Answer 1

You can use list comprehension and ternary operator to do this

lst =['-1','9','7.8']
lst = [float(numStr) if '.' in numStr else int(numStr) for numStr in lst ]

Answer 2

Here 2 simple solutions

# 1 Just convert to float.
print([float(i) for i in ['-1','9','7.8']])


# 2 Check if are dotted
convert = [float(i) if '.' in i else int(i) for i in ['-1','9','7.8']]
print(convert)

The first would work because a integer can be always converted to float. But if you really need to have the 2 differentiated then just check if are dotted.

**Solution 3 **

"Ask forgiveness not permission" just try to convert it to a int, if it fails then to a float

def int_float_converter(data):

    converted_data = []
    for d in data:
        val = None
        try:
            val = int(d)
        except ValueError:
            val = float(d)
        finally:
            if val:
                converted_data.append(val)
    return converted_data

converted = int_float_converter(['-1','9','7.8'])
print(converted)
# [-1, 9, 7.8]

Answer 3

int(x) if int(x) == float(x) else float(x)

是确定字符串是整数还是浮点数的有用方法