如何配置和启用 JMS 侦听器以根据某些条件使用消息？

Question

I have two listeners( fooMessages and barMessages ) in my application, and both of them are connected to same queue. At one point of time only one listener will consume the message from the queue based on some condition. In application.yml file if fooEnabled is set to true then fooMessages listener should consume the messages and if fooEnabled is set to false then barMessages listener should consume the messages.

Listeners:

@JMSListener(destination="${queueName}", selector = "${selectorName}")
public void fooMessages(Message message) {
   // foo logic
}
    
@JMSListener(destination="${queueName}", selector = "${selectorName}")
public void barMessages(Message message) {
   // bar logic
}

application.yml file:

queueName: myqueue
selectorName: "priority=medium"
fooEnable: true

How can I configure the listener to handle this scenario?

Answer 1

1. Give each listener an id
2. Configure the container factory to not automatically start the listeners https://docs.spring.io/spring-boot/docs/current/reference/html/application-properties.html#application-properties.integration.spring.jms.listener.auto-startup
3. Start the container(s) manually using the JmsListenerEndpointRegistry bean - registry.getListenerContainer("fooListener").start();

@Bean
ApplicationRunner runner(@Value("${fooEnabled}") boolean fooEnabled, 
        @Value("${barEnabled}") boolean barEnabled, JmsListenerEndpointRegistry registry) {
    return args -> {
        if (fooEnabled) ...
    }
}