过滤 Object 和 Typescript 中的返回键

Question

I have an object to be filtered and it should return a key that has a specific id. Id is Unique. Need an efficient logic to return this expected output.The Object to be filtered.

{
  "a":[{"id":"1123","value":"test1"}],
  "b":[{"id":"1124","value":"test2"}],
  "c":[{"id":"1125","value":"test3"}]
  
}

Input Id : "1124"

Expected Output  : 'b'

Answer 1

 let data = { "a":[{"id":"1123","value":"test1"}], "b":[{"id":"1124","value":"test2"}], "c":[{"id":"1125","value":"test3"}] }; let input = "1124"; let result = Object.entries(data).filter(([k,v]) => v[0].id === input)[0][0]; console.log(result);

Answer 2

Efficiencies here:

• break the loop as soon as something is found
• not interested in the object that has the id, only in checking that something there has that id

 o = { "a":[{"id":"1123","value":"test1"}], "b":[{"id":"1124","value":"test2"}], "c":[{"id":"1125","value":"test3"}] } for (key in o) { if (o[key].some(x => x.id === '1124')) { console.log(key); break; } }

Answer 3

 const input = "1124" const obj = { "a":[{"id":"1123","value":"test1"}], "b":[{"id":"1124","value":"test2"}], "c":[{"id":"1125","value":"test3"}] } Object.values(obj).filter((ob, i)=>{if(ob[0].id === input){console.log(Object.keys(obj)[i])}})