[英]Filter an Object and Return Key in Typescript
我有一個要過濾的 object,它應該返回一個具有特定 ID 的密鑰。 ID 是唯一的。 需要一個有效的邏輯來返回這個預期的 output。要過濾的 Object。
{
"a":[{"id":"1123","value":"test1"}],
"b":[{"id":"1124","value":"test2"}],
"c":[{"id":"1125","value":"test3"}]
}
輸入 ID :“1124”
Expected Output : 'b'
let data = { "a":[{"id":"1123","value":"test1"}], "b":[{"id":"1124","value":"test2"}], "c":[{"id":"1125","value":"test3"}] }; let input = "1124"; let result = Object.entries(data).filter(([k,v]) => v[0].id === input)[0][0]; console.log(result);
這里的效率:
o = { "a":[{"id":"1123","value":"test1"}], "b":[{"id":"1124","value":"test2"}], "c":[{"id":"1125","value":"test3"}] } for (key in o) { if (o[key].some(x => x.id === '1124')) { console.log(key); break; } }
const input = "1124" const obj = { "a":[{"id":"1123","value":"test1"}], "b":[{"id":"1124","value":"test2"}], "c":[{"id":"1125","value":"test3"}] } Object.values(obj).filter((ob, i)=>{if(ob[0].id === input){console.log(Object.keys(obj)[i])}})
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