有没有办法可以将某些特定单词替换为某些特定单词？

Question

I know this is a very basic question that can do with.replace (but I think i'll have to make a lot of.replace), and for me, is there any cleaner way to do it, because I'm still learning Python, I still don't know plenty of stuff in this language, so please pardon me. (Whenever I search "How to replace a word with a word, it only shows.replace method, so I don't know if there's another method for this.)

What a replace can do:

I have read this example on W3schools

txt = "I like bananas"

x = txt.replace("bananas", "apples")

But what I want is, in 1 input, sometimes, for example, I might write JS and it'll become Javascript , p , it'll become Python , or let's say fb , it'll become Facebook , etc, I mean, it's a lot of some words I want to replace it from shortcut words into properly words

Can I somehow use 1 variable but it stores some sort of "Shortcut words" and then replaces it with 1 variable that stores properly word?

For example:

shortcutWord = {js, fb, p}

properlyWord = {Javascript, Facebook, Python}

And it'll understand like, js suitable for Javascript, fb for Facebook, etc, I don't know how to describe it specifically, but is there a way to do it? Thanks.

Answer 1

Does this answer your question?

All you need is to input 2 parallel arrays that have the shortcuts and the long words. This could be written nicer through the use of dictionaries, however, I assumed you required the two parallel arrays.

shortcut_word = ["js", "fb", "p"]

properly_word = ["Javascript", "Facebook", "Python"]

txt = "I like js and i use fb"

def properfySentence(txt, shortcuts, full_words):
    words = txt.split(' ') # split the sentence into an array of words

    for word in words: # loop through the words...
        if word in shortcuts: # and check if the word is in the shortcuts
            words[words.index(word)] = full_words[shortcuts.index(word)] # replace the shortcut with the full length word

    txt_changed = ' '.join(words) # rejoin the words with spaces
    
    return txt_changed # return the result

print(
    properfySentence(txt,shortcut_word,properly_word)
)

Answer 2

You can use the following Syntax:

txt = "I like FB"
x = txt.replace({'js': 'javascript', 'fb': 'facebook', 'FB' : 'Facebook' })
print(x) 

Answer 3

You can create a replace() function based on the re module (regular expressions) leveraging its capacity to replace patterns with a function or lambda:

import re
def replace(s,d):
    pattern = r"\b("+"|".join(map(re.escape,sorted(d,key=len)[::-1]))+r")\b" 
    return re.sub(pattern,lambda m:d[m.group()],s)

subs = {"js":"javascript","fb":"Facebook","py":"Python"}    
text = "I love py but I despise js and fb"

print(replace(text,subs))

I love Python but I despise javascript and Facebook

The pattern is formed using the pipe ( | ) operator to select any of the keywords in the dictionary (enclosed in \b(...)\b to search for whole words). The replacement function uses the key to get the corresponding replacement value from the dictionary. The keywords are ordered in decreasing length because the pipe operator is not greedy and we want it to find the longer keywords if there are shorter keywords that are a prefix of a longer one.