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如何在 F_{2^8} 中进行加法和乘法运算

[英]How to perform addition and multiplication in F_{2^8}

I want to perform addition and multiplication in F_{2^8}我想在 F_{2^8} 中执行加法和乘法

I currently have this code which seems to work for add but doesn't work for multiply;我目前有这个代码,它似乎适用于加法,但不适用于乘法; the issue seems to be that when I modulo by 100011011 (which represents x^8 + x^4 + x^3 + x + 1), it doesn't seem to do it.问题似乎是,当我以 100011011 取模(表示 x^8 + x^4 + x^3 + x + 1)时,它似乎没有这样做。 Another idea would be to use numpy.polynomial but it isn't as intuitive.另一个想法是使用 numpy.polynomial 但它不是那么直观。

def toBinary(self, n):
    return ''.join(str(1 & int(n) >> i) for i in range(8)[::-1])

def add(self, x, y):
    """
     "10111001" + "10010100" = "00101101"
    """

    if len(x)<8:
        self.add('0'+x,y)
    elif len(y)<8:
        self.add(x,'0'+y)

    try:
        a = int(x,2); b = int(y,2)
        z = int(x)+int(y)
        s = ''
    
        for i in str(z):
            if int(i)%2 == 0:
                s+='0'
            else:
                s+='1'
    except:
        return '00000000'

    return s
    
def multiply(self, x, y):
    """
    "10111001" * "10010100" = "10110010"
    """
    if len(x)<8:
        self.multiply('0'+x,y)
    elif len(y)<8:
        self.multiply(x,'0'+y)

    result = '00000000'

    result = '00000000'
    while y!= '00000000' :
        print(f'x:{x},y:{y},result:{result}')
        if int(y[-1]) == 1 :
            result = self.add(result ,x)
            y = self.add(y, '00000001')
        x = self.add(self.toBinary(int(x,2)<<1),'100011011')
        y = self.toBinary(int(y,2)>>1) #b = self.multiply(b,inverse('00000010'))
    return result

For GF(2^n), both add and subtract are XOR.对于 GF(2^n),加法和减法都是 XOR。 This means multiplies are carryless and divides are borrowless.这意味着乘法是无进位的,除法是无借的。 The X86 has a carryless multiply for XMM registers, PCLMULQDQ. X86 具有用于 XMM 寄存器的无进位乘法 PCLMULQDQ。 Divide by a constant can be done with carryless multiply by 2^64 / constant and using the upper 64 bits of the product.除以常数可以通过无进位乘以 2^64 / 常数并使用乘积的高 64 位来完成。 The inverse constant is generated using a loop for borrowless divide.逆常数是使用无借除法循环生成的。

The reason for this is GF(2^n) elements are polynomials with 1 bit coefficients, (the coefficients are elements of GF(2)).原因是 GF(2^n) 元素是具有 1 位系数的多项式,(系数是 GF(2) 的元素)。

For GF(2^8), it would be simpler to generate exponentiate and log tables.对于 GF(2^8),生成指数表和对数表会更简单。 Example C code:示例 C 代码:

#define POLY (0x11b)
/* all non-zero elements are powers of 3 for POLY == 0x11b */
/* ... */
static uint8_t exp2[256];
static uint8_t log2[256];
/* ... */
static void Tbli()
{
uint8_t *p0, *p1;
int d0;
    d0 = 0x01;                      /* init exp2 table */
    p0 = exp2;
    for(p1 = p0+256; p0 < p1;){
        *p0++ = d0;
        d0 = (d0<<1)^d0;            /*  powers of 3 */
        if(d0 & 0x100)
            d0 ^= POLY;}
    
    p0 = exp2;                      /* init log2 table */
    p1 = log2;
    *p1 = 0;
    for(d0 = 0; d0 < 255; d0 += 1)
        *(p1+*p0++) = d0;
}
/* ... */
static BYTE GFMpy(BYTE m0, BYTE m1) /* multiply */
{
int m2;
    if(0 == m0 || 0 == m1)
        return(0);
    m2 = log2[m0] + log2[m1];
    if(m2 > 255)
        m2 -= 255
    return(exp[m2]);
}
/* ... */
static BYTE GFDiv(BYTE m0, BYTE m1) /* divide */
{
int m2;
    if(0 == m0)
        return(0);
    m2 = log2[m0] - log2[m1];
    if(m2 < 0)
        m2 += 255;
    return(alog2[m2]);
}

I created a Python package galois that extends NumPy arrays over finite fields.我创建了一个 Python package伽罗瓦,它将 NumPy ZA3CBC3F9D0C2F2C19CZE 扩展到有限域 671F2C19CZE。 Working with GF(2^8) is quite easy, see my below example.使用GF(2^8)非常容易,请参见下面的示例。

In [1]: import galois

In [2]: GF = galois.GF(2**8, irreducible_poly="x^8 + x^4 + x^3 + x + 1")

In [3]: print(GF.properties)
GF(2^8):
  characteristic: 2
  degree: 8
  order: 256
  irreducible_poly: x^8 + x^4 + x^3 + x + 1
  is_primitive_poly: False
  primitive_element: x + 1

# Your original values from your example
In [4]: a = GF(0b10111001); a
Out[4]: GF(185, order=2^8)

In [5]: b = GF(0b10010100); b
Out[5]: GF(148, order=2^8)

In [6]: c = a * b; c
Out[6]: GF(178, order=2^8)

# You can display the result as a polynomial over GF(2)
In [7]: GF.display("poly");

# This matches 0b10110010
In [8]: c
Out[8]: GF(x^7 + x^5 + x^4 + x, order=2^8)

You can work with arrays too.您也可以使用 arrays。

In [12]: a = GF([1, 2, 3, 4]); a
Out[12]: GF([1, 2, 3, 4], order=2^8)

In [13]: b = GF([100, 110, 120, 130]); b
Out[13]: GF([100, 110, 120, 130], order=2^8)

In [14]: a * b
Out[14]: GF([100, 220, 136,  62], order=2^8)

It's open source, so you can review all the code.它是开源的,因此您可以查看所有代码。 Here's a snippet of multiplication in GF(2^m) .这是GF(2^m)中的乘法片段。 All of the inputs are integers.所有输入都是整数。 Here's how to perform the "polynomial multiplication" using integers with characteristic 2.以下是如何使用具有特征 2 的整数执行“多项式乘法”。

    def _multiply_calculate(a, b, CHARACTERISTIC, DEGREE, IRREDUCIBLE_POLY):
        """
        a in GF(2^m), can be represented as a degree m-1 polynomial a(x) in GF(2)[x]
        b in GF(2^m), can be represented as a degree m-1 polynomial b(x) in GF(2)[x]
        p(x) in GF(2)[x] with degree m is the irreducible polynomial of GF(2^m)

        a * b = c
            = (a(x) * b(x)) % p(x) in GF(2)
            = c(x)
            = c
        """
        ORDER = CHARACTERISTIC**DEGREE

        # Re-order operands such that a > b so the while loop has less loops
        if b > a:
            a, b = b, a

        c = 0
        while b > 0:
            if b & 0b1:
                c ^= a  # Add a(x) to c(x)

            b >>= 1  # Divide b(x) by x
            a <<= 1  # Multiply a(x) by x
            if a >= ORDER:
                a ^= IRREDUCIBLE_POLY  # Compute a(x) % p(x)

        return c

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