[英]Is input contains all numbers from 0-9 JS
Hey guys im struggling with this exercise.嘿,伙计们,我正在为这个练习而苦苦挣扎。 Im trying to check is input contains all numbers from 0-9.我试图检查输入是否包含 0-9 的所有数字。 For example if input is "0a1b2345asd6s7e89" it should return true, "123789" it should be false.例如,如果输入是“0a1b2345asd6s7e89”它应该返回真,“123789”它应该是假的。 I tryed code below but i got feeling that im heading in wrong direction.我尝试了下面的代码,但我觉得我正朝着错误的方向前进。 Maybe regexp?也许正则表达式? Please help.请帮忙。
const test = (input) => { const arrayOfNumbers = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] const inputArray = [...input] inputArray.every(el => { arrayOfNumbers.forEach(elNumber => { elNumber === el }) }) }
const test = (a, b) => a.every(el => b.includes(el) ? true : false)
Then you can use it like然后你可以像这样使用它
const ax = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
var ab = "0a1b2345asd6s7e8"
test(ax,ab)
// -> false
ab = "0a1b2345asd6s7e89"
test(ax,ab)
// -> true
Try every
and includes
:尝试every
, includes
:
const test = input => [...Array(10).keys()].every(digit => input.includes(digit)); console.log("Expected output - true:", test("0a1b2345asd6s7e89")); console.log("Expected output - false:", test("123789"));
[...Array(10).keys()]
is an array of 0 to 9. The callback to .every()
makes sure that the input contains each digit at least once. [...Array(10).keys()]
是一个 0 到 9 的数组。对.every()
的回调确保输入包含每个数字至少一次。
in this solution i used include()
and indexOf()
在这个解决方案中,我使用了include()
和indexOf()
include: to verifie if test(input string) contains number from 0-9包括:验证测试(输入字符串)是否包含 0-9 的数字
indexoOf: to verifie if numbers are from 0-9 (ascending order) indexoOf:验证数字是否从 0-9(升序)
Solution:解决方案:
function Test(){
let ContAllNumber = 0; //0 = false, 1 = true
var test = "0a1b2345asd6s7e89";
const arrayNum = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0];
for(let i = 0; i < test.length; i++){
if(test.includes(i)){
arrayNum[i] = test.indexOf(i);
}
else{
break;
}
}
for(let i = 0; i < 9; i++){
if(arrayNum[i] < arrayNum[i+1]){
ContAllNumber = 1;
}
else{
ContAllNumber = 0;
break;
}
}
console.log(ContAllNumber);
//condition : contains number from 0 - 9
//example respecting condition: 0123456789, 0a1b2345asd6s7e89
//example NOT respecting condition: 7193456082 , a0s93as0j4
} }
Debuggin:调试:
(I recommend you to try it to understand code better) (我建议您尝试它以更好地理解代码)
function Test(){
let ContAllNumber = 0; //0 = false, 1 = true
var test = "0123456789";
const arrayNum = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0];
for(let i = 0; i < test.length; i++)
{
if(test.includes(i))
{
arrayNum[i] = test.indexOf(i);
console.log("number: " + i);
console.log("position: " + arrayNum[i]);
}
}
for(let i = 0; i < 9; i++)
{
if(arrayNum[i] < arrayNum[i+1])
{
ContAllNumber = 1;
console.log("position of number " + i + " is " + arrayNum[i] + " and position of the next number " + (i + 1) + " is " + arrayNum[i+1] + "so it's respecting condition (ok)");
console.log("so you can return 1 (true)");
}
else
{
ContAllNumber = 0;
console.log("position of number " + i + " is " + arrayNum[i] + " and position of the next number " + (i + 1) + " is " + arrayNum[i+1] + "it is NOT respecting condition (NOT OK)");
console.log("so you can return 0 (false)");
break;
}
}
console.log(ContAllNumber);
//condition = contains number from 0 - 9
//example respecting condition: 0123456789, 0a1b2345asd6s7e89
//example NOT respecting condition: 7193456082 , a0s93as0j4
}
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