輸入是否包含 0-9 JS 的所有數字

Question

嘿，伙計們，我正在為這個練習而苦苦掙扎。 我試圖檢查輸入是否包含 0-9 的所有數字。 例如，如果輸入是“0a1b2345asd6s7e89”它應該返回真，“123789”它應該是假的。 我嘗試了下面的代碼，但我覺得我正朝着錯誤的方向前進。 也許正則表達式？ 請幫忙。

 const test = (input) => { const arrayOfNumbers = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] const inputArray = [...input] inputArray.every(el => { arrayOfNumbers.forEach(elNumber => { elNumber === el }) }) }

Answer 1

const test = (a, b) => a.every(el => b.includes(el) ? true : false)

然后你可以像這樣使用它

const ax = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
var ab = "0a1b2345asd6s7e8"
test(ax,ab)
// -> false
ab = "0a1b2345asd6s7e89"
test(ax,ab)
// -> true

Answer 2

嘗試every ， includes ：

 const test = input => [...Array(10).keys()].every(digit => input.includes(digit)); console.log("Expected output - true:", test("0a1b2345asd6s7e89")); console.log("Expected output - false:", test("123789"));

[...Array(10).keys()]是一個 0 到 9 的數組。對.every()的回調確保輸入包含每個數字至少一次。

Answer 3

在這個解決方案中，我使用了include()和indexOf()

包括：驗證測試（輸入字符串）是否包含 0-9 的數字

indexoOf：驗證數字是否從 0-9（升序）

解決方案：

function Test(){
let ContAllNumber = 0; //0 = false, 1 = true

var test = "0a1b2345asd6s7e89";  
const arrayNum = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0];

for(let i = 0; i < test.length; i++){
    if(test.includes(i)){
        arrayNum[i] = test.indexOf(i);
    }
    else{
        break;
    }
}

for(let i = 0; i < 9; i++){
    if(arrayNum[i] < arrayNum[i+1]){
        ContAllNumber = 1; 
    }
    else{
        ContAllNumber = 0; 
        break;
    }
}   

console.log(ContAllNumber);

//condition : contains number from 0 - 9
//example respecting condition: 0123456789, 0a1b2345asd6s7e89
//example NOT respecting condition: 7193456082 , a0s93as0j4

}

調試：

（我建議您嘗試它以更好地理解代碼）

function Test(){
let ContAllNumber = 0; //0 = false, 1 = true

var test = "0123456789";  
const arrayNum = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0];

for(let i = 0; i < test.length; i++)
{
    if(test.includes(i))
    {
        arrayNum[i] = test.indexOf(i);
        console.log("number: " + i);
        console.log("position: " + arrayNum[i]);
    }
}

for(let i = 0; i < 9; i++)
{
    if(arrayNum[i] < arrayNum[i+1])
    {
        ContAllNumber = 1; 
        console.log("position of number " + i + " is " + arrayNum[i] + " and position of the next number " + (i + 1) + " is " + arrayNum[i+1] + "so it's respecting condition (ok)");
        console.log("so you can return 1 (true)");
    }
    else
    {
        ContAllNumber = 0; 
        console.log("position of number " + i + " is " + arrayNum[i] + " and position of the next number " + (i + 1) + " is " + arrayNum[i+1] + "it is NOT respecting condition (NOT OK)");
        console.log("so you can return 0 (false)");
        break;
    }
}   

console.log(ContAllNumber);

//condition = contains number from 0 - 9
//example respecting condition: 0123456789, 0a1b2345asd6s7e89
//example NOT respecting condition: 7193456082 , a0s93as0j4
 }