如何根据 sql 中不同列中的标识符按列中的值排序

Question

This would be our input:

NAME	YEAR	VALUES
A	2001	10
A	2000	5
A	TOTAL	15
B	2010	3
B	2011	7
B	TOTAL	10

We have to sort this table by ascending values of 'TOTAL' and then by ascending values of YEAR within the same NAME.

This would be our output:

NAME	YEAR	VALUES
B	2010	3
B	2011	7
B	TOTAL	10
A	2000	5
A	2001	10
A	TOTAL	15

Answer 1

I think I'd sum all values partitioned by name in a CTE, sort by them, then name, then year (with a special case for total)

WITH cte AS (
    SELECT *, SUM(values) OVER(PARTITION BY name) as sumval
    FROM yourdata
)

SELECT name, year, values
FROM cte
ORDER BY sumval, name, CASE WHEN year = 'TOTAL' THEN '9999' ELSE year end

You could also join your data to itself on just the total lines, meaning every row of yourdata ends up with an associated totals row:

SELECT yourdata.*
FROM
  yourdata
  INNER JOIN (SELECT name, values FROM yourdata WHERE year = 'TOTAL') t
  ON t.name = yourdata.name
ORDER BY
  t.values, yourdata.name, CASE WHEN year = 'TOTAL' THEN '9999' ELSE year end

eg

B   2010    3   TOTAL   10
B   2011    7   TOTAL   10
B   TOTAL   10  TOTAL   10
A   2000    5   TOTAL   15
A   2001    10  TOTAL   10
A   TOTAL   15  TOTAL   10

The final column is the total row for the name repeated over and over, so you can sort by the total, then by name to break ties, then by year (with 9999 to put the total after the numeric years)