获取行中每个值的最常见值 - pandas df

Question

This may be a duplicate please let me know.

I have a pandas df like this:

id	name	Common
One	A
One	A
One	A
One	B
Two	C

I'd like to output something like this:

Where the most common name for each id is placed in the common column.

id	name	Common
One	A	A
One	A	A
One	A	A
One	B	A
Two	C	C

I've tried this but at this point i'm throwing darts in the dark

df.groupby(['id', 'name']).agg(lambda x:x.value_counts().index[0])

Answer 1

This works:

df['Common'] = df.groupby('id')['name'].transform(lambda x: x.mode()[0])

Output:

>>> df
    id name Common
0  One    A      A
1  One    A      A
2  One    A      A
3  One    B      A
4  Two    C      C

Answer 2

A longer process is to pivot and map:

df.assign(Common = df.id.map(df.pivot(None, 'id', 'name').mode().T.squeeze()))
 
    id name Common
0  One    A      A
1  One    A      A
2  One    A      A
3  One    B      A
4  Two    C      C