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如何从一个字符串中拆分出 ipv6 和 ipv4?

[英]How to split up ipv6 and ipv4 from one string?

i have a library that passes me a string for the users ip address that looks like this- "::ffff:10.10.102.86"我有一个库,它为用户 ip 地址传递了一个字符串,看起来像这样-“::ffff:10.10.102.86”

I don't want to change the code in that library for many reasons.出于多种原因,我不想更改该库中的代码。 Obviously the leftmost side is ipv6 and the rightmost side is v4.显然最左边是ipv6,最右边是v4。

What is the best way to split this up into two strings for v6 and v4?将其拆分为 v6 和 v4 的两个字符串的最佳方法是什么?

I've tried some other regex matches but these did not work:我尝试了其他一些正则表达式匹配,但这些都不起作用:

var ipv6 = ip.match(/^(?:(?:[a-fA-F\d]{1,4}:){7}(?:[a-fA-F\d]{1,4}|:)|(?:[a-fA-F\d]{1,4}:){6}(?:(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)(?:\\.(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}|:[a-fA-F\d]{1,4}|:)|(?:[a-fA-F\d]{1,4}:){5}(?::(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)(?:\\.(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}|(?::[a-fA-F\d]{1,4}){1,2}|:)|(?:[a-fA-F\d]{1,4}:){4}(?:(?::[a-fA-F\d]{1,4}){0,1}:(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)(?:\\.(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}|(?::[a-fA-F\d]{1,4}){1,3}|:)|(?:[a-fA-F\d]{1,4}:){3}(?:(?::[a-fA-F\d]{1,4}){0,2}:(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)(?:\\.(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}|(?::[a-fA-F\d]{1,4}){1,4}|:)|(?:[a-fA-F\d]{1,4}:){2}(?:(?::[a-fA-F\d]{1,4}){0,3}:(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)(?:\\.(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}|(?::[a-fA-F\d]{1,4}){1,5}|:)|(?:[a-fA-F\d]{1,4}:){1}(?:(?::[a-fA-F\d]{1,4}){0,4}:(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)(?:\\.(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}|(?::[a-fA-F\d]{1,4}){1,6}|:)|(?::(?:(?::[a-fA-F\d]{1,4}){0,5}:(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)(?:\\.(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}|(?::[a-fA-F\d]{1,4}){1,7}|:)))(?:%[0-9a-zA-Z]{1,})?$/gm);

var ipv4 = ip.match(/^(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)(?:\.(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}$/gm);
            

Appreciate any help you can give!感谢您提供的任何帮助!

I would just do it like this instead of creating very complicated regEx expressions.我会这样做,而不是创建非常复杂的正则表达式。

const arr = "::ffff:10.10.102.86".split(':')
const ipV4 = arr.pop()
const ipV6 = arr.join(':')

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