如何从一个字符串中拆分出 ipv6 和 ipv4？

Question

我有一个库，它为用户 ip 地址传递了一个字符串，看起来像这样-“::ffff:10.10.102.86”

出于多种原因，我不想更改该库中的代码。 显然最左边是ipv6，最右边是v4。

将其拆分为 v6 和 v4 的两个字符串的最佳方法是什么？

我尝试了其他一些正则表达式匹配，但这些都不起作用：

var ipv6 = ip.match(/^(?:(?:[a-fA-F\d]{1,4}:){7}(?:[a-fA-F\d]{1,4}|:)|(?:[a-fA-F\d]{1,4}:){6}(?:(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)(?:\\.(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}|:[a-fA-F\d]{1,4}|:)|(?:[a-fA-F\d]{1,4}:){5}(?::(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)(?:\\.(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}|(?::[a-fA-F\d]{1,4}){1,2}|:)|(?:[a-fA-F\d]{1,4}:){4}(?:(?::[a-fA-F\d]{1,4}){0,1}:(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)(?:\\.(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}|(?::[a-fA-F\d]{1,4}){1,3}|:)|(?:[a-fA-F\d]{1,4}:){3}(?:(?::[a-fA-F\d]{1,4}){0,2}:(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)(?:\\.(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}|(?::[a-fA-F\d]{1,4}){1,4}|:)|(?:[a-fA-F\d]{1,4}:){2}(?:(?::[a-fA-F\d]{1,4}){0,3}:(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)(?:\\.(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}|(?::[a-fA-F\d]{1,4}){1,5}|:)|(?:[a-fA-F\d]{1,4}:){1}(?:(?::[a-fA-F\d]{1,4}){0,4}:(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)(?:\\.(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}|(?::[a-fA-F\d]{1,4}){1,6}|:)|(?::(?:(?::[a-fA-F\d]{1,4}){0,5}:(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)(?:\\.(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}|(?::[a-fA-F\d]{1,4}){1,7}|:)))(?:%[0-9a-zA-Z]{1,})?$/gm);

var ipv4 = ip.match(/^(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)(?:\.(?:25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}$/gm);
            

感谢您提供的任何帮助！

Answer 1

我会这样做，而不是创建非常复杂的正则表达式。

const arr = "::ffff:10.10.102.86".split(':')
const ipV4 = arr.pop()
const ipV6 = arr.join(':')