email Python 的非贪婪正则表达式模式

Question

I m new to regular expression and stuck at this situation where my current regex pattern is returning two results and one of them starting with the phone no. (String doesn't have a space between phone no and email). I tried using the? to make expression non greedy but its not returning anything.

Code

pattern = re.compile(r'\b[A-Za-z0-9._%.?-]+@[A-Za-z0-9.-]+\.[A-Z|a-z]{2,}\b')

matches = pattern.finditer(Clean)

for match in matches:
   print(match.group(0))

Output

9012345678testemail.grp@gmail.com
support@testtest.com

Answer 1

I guess what you are looking for is:

pattern = re.compile(r"[a-zA-Z]+[\w.-]*@[a-z]+[.][a-z]+")

[a-zA-Z] -> the email starts with a letter

\w -> any letter, digit or an underscores

[\w.-]* -> 0 or more letters, digits, underscores, ., or -

[az]+ -> a lower case domain 1 or more characters long

[.] -> put the . in square brackets, cuz. has a special meaning in regex

pattern = re.compile(r"[a-zA-Z]+[\w.-]*@[a-z]+[.][a-z]+")
matches = pattern.findall("aar@g.com ooo11..com hellow_world@hello.world 1234hey@hey.com")
print(matches)

Result:

['aar@g.com', 'hellow_world@hello.world', 'hey@hey.com']