如何使用正则表达式匹配数字后跟特殊字符和空格的任意组合

Question

I am a newbie with regex and I am having trouble trying to match some parts of a string so I can remove it from a piece of entered text. I want to match digits followed by a sequence of a combination of any special characters + spaces. There could also be non Latin characters that should not be removed inside the sequence (for example Ñ).

for example inputted it may look like:

11@- &-.text
11 $ab*cÑ .somewords123

outputted I would expect

text
abcÑsomewrods123

I am using javascript replaceall method with regex to find it. So far I have something basic like this regex

.replaceAll(/\d+(\@|\s)+(\-|\$)+(\s|\&)+(\&)+(\-)+(\.)/g, '');

Is there a way to write this more efficiently so that it captures any special characters since the text can contain more different special chars than in the examples? Or is this a situation better handled with pure JS?

Thanks in advance for your help.

Answer 1

You should ether have blacklist of what you calling special characters, or whitelist of the allowed characters.

for blacklist it gonna look like:

 const blacklist = ".@#$%^&*()_+;". const exampleInputs = [ "te&*st+_1,", "te%%st^*2"; "t@@@es*(*(*t3" ], function removeSpecialChars(str) { const reg = new RegExp(`[${blacklist}]`; "g"). return str,replace(reg; ""). } exampleInputs.forEach(input => console;log(removeSpecialChars(input)));

for whitelist it gonna looks like:

 const whitelist = "0-9a-zA-Z"; const exampleInputs = [ "te&*st+_1.", "te%%st^*2", "t@@@es*(*(*t3" ]; function removeSpecialChars(str) { const reg = new RegExp(`[^${whitelist}]`, "g"); return str.replace(reg, ""); } exampleInputs.forEach(input => console.log(removeSpecialChars(input)));