如何将参数传递给python中的timeit function？

Question

import timeit
#those are the parameters that need to be passed
list1=["Ahmed","Ahmedd"]
#loop through the parameters
for x in list1:
mysetup=x
#the function to be tested 
mycode='''
#testing if the string is unique
def is_unique_chars_using_set(string):
#Solution Using Set
characters_seen = set()
for char in string:
    if char in characters_seen:
        return False
    characters_seen.add(char)
return True'''
print (timeit.timeit(stmt = mycode,number = 1000000))

How to pass those parameters to timeit ?

Answer 1

The code here doesn't uses the list actually. The timeit cannot look inside the loop. (ie. It should be in proper range)

The code below will work for you

import timeit
#those are the parameters that need to be passed
list1=["Ahmed","Ahmedd"]
#loop through the parameters

#the function to be tested 
mycode='''
#testing if the string is unique
def is_unique_chars_using_set(string):
    #Solution Using Set
    characters_seen = set()
    for char in string:
        if char in characters_seen:
            return False
        characters_seen.add(char)
    return True'''
print (timeit.timeit(stmt = mycode,number = 1000000))

If the for loop is needed, Then you need to include the for loop inside the "my code"

import timeit
mycode='''
list1=["Ahmed","Ahmedd"]
for x in list1:
    mysetup=x
    #testing if the string is unique
    def is_unique_chars_using_set(string):
        #Solution Using Set
        characters_seen = set()
        for char in string:
            if char in characters_seen:
                return False
            characters_seen.add(char)
        return True'''
print (timeit.timeit(stmt = mycode,number = 1000000))